Question

-x^2-4x-4=0
x=1

Answer 1

if i take (-1) common then i will be left with this equation
\[{{-1}(x^2+4x+4)}=0\]

Answer 2

now -1 cannot be equal tozero hence
\[x^2 + 4x + 4 =0\]
now solve for x

Answer 3

x=-9

Answer 4

no it is \[(a+b)^2 = a^2 + 2ab + b^2\]

Answer 5

what is x=1 in your question???

Answer 6

we are using 1 for x. we are doing a parabola.