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Mathematics 11 Online
OpenStudy (anonymous):

help with polynomials?

OpenStudy (anonymous):

(3AB+Asquared +Bsquared) + (4Bsquared - 3AB + 3Asquared)

OpenStudy (alexwee123):

hunger games :D

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

can you guys help me

OpenStudy (accessdenied):

\((3AB + A^2 + B^2) + (4B^2 - 3AB + 3A^2)\) Add together like-terms. \(kA^2 + hA^2 = (k + h)A^2\), \(kAB + hAB = (k + h)AB\), etc.

OpenStudy (accessdenied):

You can reorder the expression using the commutative and associative properties of addition (nothing multiplied to the parentheses, its just addition so we can remove them): \((3AB - 3AB) + (A^2 + 3A^2) + (B^2 + 4B^2)\) Then you just add the coefficients together. Makes sense?

OpenStudy (anonymous):

it helps a bit

OpenStudy (accessdenied):

Then by factoring: \((3 - 3)AB + (1 + 3)A^2 + (1+4)B^2\) Simplifying, we get \(0AB + 4A^2 + 5B^2 \\ = \mathbf{4A^2 + 5B^2}\)

OpenStudy (anonymous):

yah thats right i get it thanks

OpenStudy (accessdenied):

The less rigorous approach is pretty much just looking at the like terms, usually faster than doing the "pair the like terms, factor, and simplify" stuff: Once you simplify it to only addition and subtractions: \(\color{green}{3AB} + \color{purple}{A^2} + \color{red}{B^2} + \color{red}{4B^2} \color{green}{- 3AB} + \color{purple}{3A^2}\) The \(3AB\) and \(-3AB\) cancel, add coefficients of \(A^2\) and \(B^2\) terms You're welcome. :)

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