Question

Attachment.

Answer 1

This one, I thought, was confusing because you can't really factor it.

Answer 2

same as before... with intersecting chords

(x-2)(x+7)=4(2x-1)

x^2 + 5x - 14 = 8x - 4

or

x^2 -3x - 10 = 0


factorise

only consider the positive solution because you are dealing with measurements

Answer 3

I don't know how you could find the x with those numbers.

Answer 4

Well, maybe with the quadratic formula, but I'm not good at using it.

Answer 5

well I think it factorises to

(x -5)(x+2) = 0

then x = 5, -2

only consider 5 as the solution... using -2 will give negative measurements

Answer 6

4(2x-1) = (x-2)(x+7)
-x^2 + 3x + 10 = 0
x^2 - 3x - 10 = 0
(x +2)(x-5) = 0
x = -2 or x = 5

Answer 7

@Sakigirl --> It factors over the integers.