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This one, I thought, was confusing because you can't really factor it.
same as before... with intersecting chords (x-2)(x+7)=4(2x-1) x^2 + 5x - 14 = 8x - 4 or x^2 -3x - 10 = 0 factorise only consider the positive solution because you are dealing with measurements
I don't know how you could find the x with those numbers.
Well, maybe with the quadratic formula, but I'm not good at using it.
well I think it factorises to (x -5)(x+2) = 0 then x = 5, -2 only consider 5 as the solution... using -2 will give negative measurements
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4(2x-1) = (x-2)(x+7) -x^2 + 3x + 10 = 0 x^2 - 3x - 10 = 0 (x +2)(x-5) = 0 x = -2 or x = 5
@Sakigirl --> It factors over the integers.
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