Question

determine an equation of the line tangent to the curve at the specified point: y=e^(2x)? points are (1,e^2) Could someone please explain the steps?

Answer 1

find 1st derivative

\[y' = 2e^2x\]

sunstitute x = 1 into the 1st derivative to find the gradient of the tangent at x = 1

now you have m and the point (1, e^2)

use the point slope formula for the equation of the tangent

Answer 2

Thanks!!