Question

what is the equation of a hyperbola with vertices at 0,6 and 0,6 and foci at 0,8 and 0,8

x^2/64-y^2/36=1

y^2/64-x^2/36=1

x^2/36-y^2/28=1

y^2/36-x^2/28=1

Answer 1

i'm thinking you mean 0, -6 and 0, 6 for vertices and foci 0,-8 and 0,8 ?

Answer 2

hello?

Answer 3

i think option 4 is correct