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Mathematics 16 Online
OpenStudy (anonymous):

what is the equation of a hyperbola with vertices at 0,6 and 0,6 and foci at 0,8 and 0,8 x^2/64-y^2/36=1 y^2/64-x^2/36=1 x^2/36-y^2/28=1 y^2/36-x^2/28=1

OpenStudy (anonymous):

i'm thinking you mean 0, -6 and 0, 6 for vertices and foci 0,-8 and 0,8 ?

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

i think option 4 is correct

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