Solving Exponential Equations with Unequal Bases
Problem:
3^(x-4)=7^(x+9)
Answer Options:
x ≈ –25.86

x ≈ –0.04

x ≈ –0.39

x ≈ –2.59

Question

Solving Exponential Equations with Unequal Bases
Problem: 
3^(x-4)=7^(x+9)
Answer Options:
x ≈ –25.86
		
x ≈ –0.04
		
x ≈ –0.39
		
x ≈ –2.59

experimentx · Answer

take log on both sides
$ \ln3^{x-4} = \ln{7^{x+9}}$
$ = (x-4)\ln 3 = (x+9)\ln7$ <--- solve this equation.

anonymous · Answer

i dont know how to solve it, i have no idea how to work these problems.

experimentx · Answer

use calculator to calculate the value of log. http://www.wolframalpha.com/input/?i=solve+%28x%E2%88%924%29ln3%3D%28x%2B9%29ln7