Question

In a Chinese game show, 50% of the players are eliminated each day. If the show starts with 1,000 players, to the nearest integer, how many players will be present at the end of the 8th day of play?

Answer 1

\[f(x)=\frac{1000}{2^x},\]where \(x\) is the number of days.

Answer 2

Or, heck, just halve that number 8 times.

Answer 3

7 times, rather.

Answer 4

what ?

Answer 5

How many at the end of the 1st day?

Answer 6

500

Answer 7

Cool. How many at the end of the second day?

Answer 8

250

Answer 9

Cool. How many at the end of the third day?

Answer 10

125

Answer 11

Keep going until you get the 8th day.

Answer 12

okay thanks

Answer 13

125/2 = 62.5
62.5/2 = 31.25
etc.