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OpenStudy (anonymous):
Which of the following is the solution to the equation 25^(z - 2) = 125?
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OpenStudy (anonymous):
take logs of both sides: ln 25^(z - 2) = ln 125 (z - 2) ln 25 = ln 125 - using laws of logarithms z-2 = ln 125/ ln25 can you finish this off?
OpenStudy (anonymous):
yeah I think I got it z=3.5 right?
OpenStudy (anonymous):
checking... yea
OpenStudy (anonymous):
correct
OpenStudy (anonymous):
ty
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