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In an examination, the number of those who passed to the number of who failed was in the ration of 3:1. Had 8 more students turned up and 6 less passed, the ratio would have been 2:1. Find how many students turned up to the exam.
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x/y = 3 now adjust x, y and the ratio to get another equation in x and y
I get the ratio for the first set of numbers. Its after eight more students are added when the problem arises.lol.
? 8 added is x+8, 6 less is y-6 etc Simultaneous equations in x and y. solve
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