Question

Solve
sqrt(x^2 + 4) = 4x

Answer 1

square both sides

Answer 2

\[x^{2}+4=16x ^{2}\]

Answer 3

can you solve this?

Answer 4

\[\sqrt(x^2+4)=4x\]
taking square on both sides
\[x^2-4=16x^2\]
\[16x^2-x^2=4\]
\[15x^2=4\]
\[x^2=4/15\]
\[x=\pm2/\sqrt(15)\]

Answer 5

@RedPrince, how did you go from\[x ^{2}+4=16x ^{2}\]to\[x ^{2}-4=16x ^{2}\]?

Answer 6

@pfenn1 by mistake correct it it is now 17 instead of 15
thanks for this