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OpenStudy (anonymous):
Is this quadratic vertex form?? y+3=1(x+1)^2
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OpenStudy (anonymous):
\[ (y+3)=4 \times \frac 1 4 \times (x+1)^2 \] The vertex is at (-1,3) and yes I think this is what they call vertex ...
OpenStudy (anonymous):
EDIT: (-1,-3)
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