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A man when asked how many hens and buffaloes he has, he told that his animals have 120 eyes and 180 legs. How many hens and buffaloes does he have?
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Let the no of hens be x and no of buffaloes be y 2x+2y=120 x+y=60-(1) 2x+4y=180 x+2y=90-(2) (2)-(1)=>y=30 (1)=>x=60-30 =30
assuming you don't have any mutated hens or buffaloes with 3 eyes or 4 legs, you can set up a system like this to solve...: |dw:1336240421183:dw|
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