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OpenStudy (anonymous):

can someone help me integrate (4xdx)/(2x+1)

OpenStudy (anonymous):

im substituting u = 2x+1

OpenStudy (anonymous):

du = 2dx

OpenStudy (anonymous):

2x+1-log(2x+1)*1/2

OpenStudy (anonymous):

2x+1-log(2x+1)

OpenStudy (anonymous):

\[\int\limits \frac{4x}{2x+1}dx\]

OpenStudy (anonymous):

* +c obviously

OpenStudy (anonymous):

|dw:1336252868637:dw|

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