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OpenStudy (anonymous):
can someone help me integrate (4xdx)/(2x+1)
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OpenStudy (anonymous):
im substituting u = 2x+1
OpenStudy (anonymous):
du = 2dx
OpenStudy (anonymous):
2x+1-log(2x+1)*1/2
OpenStudy (anonymous):
2x+1-log(2x+1)
OpenStudy (anonymous):
\[\int\limits \frac{4x}{2x+1}dx\]
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OpenStudy (anonymous):
* +c obviously
OpenStudy (anonymous):
|dw:1336252868637:dw|
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