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If \[2^x=\cos (y/2) \] & \[a^x=\sin y\] Then, Find \[\sin (y/2).\]
Please solve:)
you know the formula : \[\sin 2u = 2\sin u \cos u\] ?
Ya!
Then you have \[a^x=2\sin\frac{y}{2} \cos\frac{y}{2}\]
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a^x/2^(x+1)
ok !anakhoava
\[siny=2\sin \frac y2 \cos \frac y2\]
Thanx a lot u all!
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