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OpenStudy (mica):
prove: sin4A = 4sinAcos^3A - 4sin^3cosA
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OpenStudy (mica):
i got to 2in2a(cos2a) but how do i get that to sin4a
OpenStudy (mica):
2sin2A*
OpenStudy (mica):
i know that sin2A = 2sinAcosA but how do i work around that to get sin4A
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