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In the triangle below, what ratio is cos R?
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\(\Large \color{purple}{ cosR = {adjacent \over hypotenuse} }\)
Use the ratio that parth gave you along with the triangle picture i just sent
\(\Large \color{purple}{adjacent \rightarrow p }\) \(\Large \color{purple}{hypotenuse \rightarrow q }\) \(\Large \color{purple}{\text{The ratio required is}{ p \over q} }\)
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so it would be r over p?
No, it'd be \(\large \color{purple}{p \over q }\)
Your adjacent side is the leg that touches the angle, and the hypotenuse is across from the 90 degrees. Parth is correct
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