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Factor the GCF and then factor the resulting binomial: 50x3 - 128x
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\[x(50x^2-128)\]
GCF is Greatest Common Factor, so what is the most you can take out of both terms? \[2x(25x^{2}-64)\] Then it becomes a difference of squares problem.
\[x[(\sqrt{50}x)^2-(8\sqrt{2})^2]\]
thank you to both!
i think sashaley is more correct!
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yeah i verified it through the multiple choice answers.
good!
:)
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