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Hello.

$$\LARGE \begin{array}{l}f(x) = - {x^2} + 3\,\,\,,\,\,\,f\left( {f\left( { - 2} \right)} \right)?\\f\left( {f\left( { - 2} \right)} \right) = - {\left( { - {{\left( { - 2} \right)}^2} + 3} \right)^2} + 3\\f\left( {f\left( { - 2} \right)} \right) = - {\left( { - 4 + 3} \right)^2} + 3\\f\left( {f\left( { - 2} \right)} \right) = - {\left( { - 1} \right)^2} + 3\\f\left( {f\left( { - 2} \right)} \right) = - 1 + 3\\f\left( {f\left( { - 2} \right)} \right) = 2\end{array}$$

Question

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Hello.

$$\LARGE \begin{array}{l}f(x) =  - {x^2} + 3\,\,\,,\,\,\,f\left( {f\left( { - 2} \right)} \right)?\\f\left( {f\left( { - 2} \right)} \right) =  - {\left( { - {{\left( { - 2} \right)}^2} + 3} \right)^2} + 3\\f\left( {f\left( { - 2} \right)} \right) =  - {\left( { - 4 + 3} \right)^2} + 3\\f\left( {f\left( { - 2} \right)} \right) =  - {\left( { - 1} \right)^2} + 3\\f\left( {f\left( { - 2} \right)} \right) =  - 1 + 3\\f\left( {f\left( { - 2} \right)} \right) = 2\end{array}$$

anonymous · Answer

I want to know if I've done it right... because my multiple choices doesn't fit.

anonymous · Answer

7
1
-1
3


... there could me a mistake... that's why I'm asking.

anonymous · Answer

i cant find any mistake here

anonymous · Answer

ok.. I guess multiple choices are wrong or something. Thank you :)

unklerhaukus · Answer

i cannot see any mistakes in your working

anonymous · Answer

ok thanks :)