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sin70- sin10=?
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sin70- sin10= 2cos(70+10)/2 sin(70-10)/2= 2cos40sin30
\[\sin P - \sin Q = 2 \cos \frac{P+Q}{2}\sin \frac{P-Q}{2}\]
sin(70) = sin(90 - 20) = cos(20) [As sin(90 - x) = cos(x)]
cosx=sin(90°-x)
@shruti Could the answer be using factor formula instead? becuz I think he's asking for difference of 2 sines
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