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Mathematics 17 Online
OpenStudy (anonymous):

factor 3y^2+13y+4 so far i've got 3y^2+12y+y+4

OpenStudy (anonymous):

(4 + y) (1 + 3 y)

Parth (parthkohli):

Yes, you've got it right till here: \(\Large \color{purple}{3y(y + 4) + 1(y + 4) }\) \(\Large \color{purple}{(3y + 1)(y + 4) }\)

OpenStudy (anonymous):

parth ty so much thats the format i was looking for

Parth (parthkohli):

:)

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