The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimensions of the rectangle?
If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?
2x 2 + 3x - 119 = 0
3x 2 + 3x - 119 = 0
6x 2 - 119 = 0

Question

The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimensions of the rectangle?
If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?
2x 2 + 3x - 119 = 0
3x 2 + 3x - 119 = 0
6x 2 - 119 = 0

anonymous · Answer

3x 2 + 3x - 119 = 0

jit4won · Answer

@ParthKohli  would you like to comment on Romero

anonymous · Answer

@jit4won About?

jit4won · Answer

This Guy wrote this ..Don't write direct answers .

anonymous · Answer

@jit4won I'm well aware of the rules of this site.

jit4won · Answer

So we can write answers ?

anonymous · Answer

@jit4won Not if you want to get kicked out