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-8≤8-x≤8
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subtract 8 straight across as a start
Then you will have to multiply -1 straight across afterwards in order to get rid of the negative sign that remains next to the x. @satellite73 Do the signs change?
yes otherwise the answer would not make sense
i dont understand
\[-8\leq 8-x\leq 8\] subtract 8 from ever term \[-16\leq-x\leq0\]
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the change every sign and the sense of the inequality to get \[16\geq x\geq 0\]
which you can rewrite if you like as \[0\leq x\leq 16\] to put the smaller number on the left, but it says the same thing
kk thanks anlot Satellite
yw
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