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I have a question of how to solve an integral I'll post it in a reply
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\[\int\limits_{}^{}dx \div x \times \sin (\ln (x))\]
put ln x = u
1/x dx = du
thnx now I see how
Can you solve it now ?
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something else now I have \[\int\limits_{}^{} dx \div \sin ( \ln(u) ) \] how do I solve that?
instead of dx is du
you have some confusion. It becomes \[\int\limits {\frac{du}{\sin u}}\]
oh yes you're right :)
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