Question

Multiply

x^2-49/x^2*x^2-7x/x^2+3x-70

Answer 1

is that how it is written?

Answer 2

I might be missing somthing let me check lol

Answer 3

(x^2-49)/(x^2)*(x^2-7x)/(x^2+3x-70)

Answer 4

\[\LARGE \frac{x^2-49}{x^2}\cdot \frac{x^2-7x}{x^2+3x-70 }\]
\[\LARGE \frac{x^2-7^2}{x^2}\cdot \frac{x(x-7)}{x^2+3x-70 }\]
\[\LARGE \frac{(x-7)(x+7 )}{x^{\cancel{2}}}\cdot \frac{\cancel{x} (x-7)}{x^2+3x-70 }\]
.... try factorizing the denominator of the second fraction...

Answer 5

\[\LARGE \frac{(x-7)(x+7 )}{x}\cdot \frac{ (x-7)}{(x+10)(x-7 ) }\]
\[\LARGE \frac{(x-7)(x+7 )}{x}\cdot \frac{ \cancel{(x-7)}}{(x+10)\cancel{(x-7 )} }\]

Answer 6

now multiply them...

Answer 7

since your question says...

Multiply
x^2-49/x^2*x^2-7x/x^2+3x-70