Question

f(x)=x/(x^2-4) x-intercept(s):
(-2,0) and (2,0), correct?

Answer 1

http://www.wolframalpha.com/input/?i=f%28x%29%3Dx%2F%28x%5E2-4%29+ ?

Answer 2

no, just set the numerator =0

Answer 3

http://www.wolframalpha.com/input/?i=f%28x+%29%3D+x%2F%28x%5E2-4%29+

Answer 4

Doesn't that show the x intercept at -2 and 2??

Answer 5

Or is it (0,0)?

Answer 6

no... it shows (0, 0).
just set y=0 in your equation.

Answer 7

Oh, o.k. Thanks!

Answer 8

what you did is set the denominator =0 and that is finding the vertical asymptotes.

Answer 9

Oh I see. My mistake.

Answer 10

good work man :)