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Trig: Section - Double Angle Formulas Simplify: 1.sin(pi/12)*cos(pi/12) 2. tan(22.5)/1-tan^2(22.5) | "22.5 is in degrees" Help me please
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http://www.freemathhelp.com/trig-double-angles.html all the formulas are in there
I know the formulas but in problem number 1, there is no "2" multiplying sine or cosine?
then it is half of what you want
\[\sin(2\theta)=2\sin(\theta)\cos(\theta)\] \[\frac{1}{2}\sin(2\theta)=\sin(\theta)\cos(\theta)\]
so \[\frac{1}{2}\sin(\frac{\pi}{6})=\sin(\frac{\pi}{12})\cos(\frac{\pi}{12})\]
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