Question

Drawing an embarrassing blank. How exactly do I solve this. (6x-1)^2<1

Answer 1

square, subtract 1, solve a quadratic

Answer 2

or you could start with
\[-1\leq 6x-1\leq 1\] which might be easier

Answer 3

since
\[a^2<1\iff -1<a<1\]

Answer 4

I some how tried that but didnt get it right

Answer 5

\[-1< 6x-1<1\]
\[0<6x<2\]
\[0<x<\frac{1}{3}\] should work, is that not it?

Answer 6

ah thank god I found out what I was doing wrong

Answer 7

something silly no doubt

Answer 8

you are a hero.. so used to complex math forget the basics