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integrate: x((x+1)^6) dx using u substitution: u = (x+1); du = 1 dx; dx = 1 the first step says integrate (u-1) u^6 du how did they change the x into (u-1)?
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It's from the substitution. Since u=x+1, u-1=x. Get it? :)
\[u=x+1\] \[x=u-1\]
ahhh ok I guess I can see that if someone points it out...I am not going to see that on the final...I emphasize the I...it might be there but I won't see it.....like a mathematical snake
if it was a snake, it would have bit you
i dont like this only one best answer business grrr
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