integrate: x((x+1)^6) dx

using u substitution: u = (x+1); du = 1 dx; dx = 1

the first step says integrate (u-1) u^6 du how did they change the x into (u-1)?

Question

integrate: x((x+1)^6) dx

using u substitution: u = (x+1);  du = 1 dx; dx = 1

the first step says integrate (u-1) u^6 du     how did they change the x into (u-1)?

blockcolder · Answer

It's from the substitution. Since u=x+1, u-1=x. Get it? :)

anonymous · Answer

$$u=x+1$$
$$x=u-1$$

anonymous · Answer

ahhh ok I guess I can see that if someone points it out...I am not going to see that on the final...I emphasize the I...it might be there but I won't see it.....like a mathematical snake

anonymous · Answer

if it was a snake, it would have bit you

anonymous · Answer

i dont like this only one best answer business grrr