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a=-2 , b=-1 , c=4 , d=3 Solve) √2a-3b+4=?
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\[\sqrt{2a-3b+4}\] Is this your question?
put the values of a and b..then solve
no its 2a(then the square root of 2) +b-3c
\[\sqrt {2}a +b - 3c\] ?
yah
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Put a = -2 b=-1 and c=4 into that. \[\sqrt2a + b -3c = \sqrt 2 (-2) + (-1) -3(4) =?\]
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