Question

find the dimensions of a rectangular garden with perimeter 62 yd and area 220 yd^2

Answer 1

2a+2b=62
ab=220
Solve

Answer 2

im still confused. a=220-x?

Answer 3

a=220/b

also

2a=-2b+62
a=-b+31

Answer 4

where you get x from?

Answer 5

i meant b

Answer 6

thats a*b=220 so you have to divide a or b on both sides to seperate them

Answer 7

well i see, but where am i getting the dimentions -b+31 isnt really an answer

Answer 8

solve by substitution

Answer 9

but theres only one equation?

Answer 10

2a+2b=62
ab=220

Answer 11

You are told the perimeter, area, and that its a rectangle. so...

Answer 12

i must be missing something

Answer 13

isolate either a or b in one of the equations i gave you, then plug what X= into the OTHER equation. youll get a=number. then you plug that in and you can find b=

Answer 14

y=1?

Answer 15

i mean b

Answer 16

have you learned how to solve systems of equations by substitution or elimination?

Answer 17

well its what im learning now, so im just confused

Answer 18

watch kahn academy

http://www.khanacademy.org/math/algebra/systems-of-eq-and-ineq/v/solving-systems-by-substitution-1

Answer 19

which two equations am i substituting? you solved before so im wondering

Answer 20

2a+2b=62 is one


ab=220 is the other




2(220/b)+2b=62
b=????

Put that into the ab=220 one to find a

Answer 21

whats 2(220/b)?

Answer 22

\[{2\over1} * {220\over b} =\] cross multiply