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find the dimensions of a rectangular garden with perimeter 62 yd and area 220 yd^2
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Its a system of equation. Perimeter = 2(length) + 2(width) Area = (length) * (width)
set the Perimeter = to 62 and the area = to 220
i really just need a step by step to get the answer i dont get it whatsoever
b*h = 220 2b+2h = 62 b = 31-h substitution (31-h)*h = 220 h^2-31h+220 = 0 quadratic h = 11, 20 b = 20, 11
so dimensions are 11x20
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