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Mathematics 17 Online
OpenStudy (anonymous):

Solve for x. 2x - 1 < 7 and 5x + 3 < 3 {x | x < 0} {x | x < 4} {x | 0 < x < 4}

OpenStudy (anonymous):

2x-1<7<=>x<4 and 5x+3<3<=>x<0 <=>x<4 and x<0 <=>x<0

OpenStudy (maheshmeghwal9):

2x-1<7=>2x<8=>x<4. 5x+3<3=>5x<0=>x<0

OpenStudy (maheshmeghwal9):

hence x<0

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