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given the quadratic function y=x2+2x−3 find the coordinates of the y-ntercept.
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Put x =0 into the equation, you'll get the value of y-int
on y-axis, x = 0 so y int= -3
y=(0)^2+2(0)−3 = 0+0 -3 =?
y=-3
and for the x-intercept would you put it in as -3=x^2+2x-3
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y-int -> yes For x-int, put y=0 and solve the equation
ok im kinda confused
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