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The function g is defined by g(x) = 8x-x^2 for x>=4 State the domain and range for g^-1
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find the derivative using that: f' =1/g' the domain will be everything that's is alowed for f'
So how do you find g^-1 anyway?
u can't expres it in explicit form...
So how do you find it? Answer says domain = x>=1 and the range is g^-1(x)>=4
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