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Solve the following system of equations by the substitution method. 10x + 10y = 1 x = y - 3 What is the value of y? -29/20 31/20 -3/2
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Replace x by its value in the first equation to get 10(y-3)+ 10 y =1 Solve this equation for y
31/20
Now find x. x= y-3
10x + 10y = 1 you substitute, ill come out like this 10(y - 3) + 10y = 1 10y - 30 + 10y = 1 10y + 10y = 1 + 30 20y = 31 y = 31/20 All it is is simplifying and arranging it to isolate y, since that is what your looking for.
-29/20
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x= 31/20 -3=-29/20
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