Question

Solve the system, using substitution. Write the solution as an ordered pair (a,b)
3a - b = 11 and 2a + 3b = 0



(3, 2)

(3, -2)

(-3, 2)

(-3, -2)

no solution

Answer 1

All you have to do is simplify, and then substitute one equation onto the other i will isolate b in the first one.
3a - b = 11
-b = -3a + 11
b = 3a - 11
then enter it in the second equation
2a + 3b = 0
2a + 3(3a - 11) = 0
simplify
2a + 9a - 33 = 0
11a = 0 + 33
11a = 33
a = 33 / 11
a = 3
the i plot my a answer in the equations to find the answer for b
3a - b = 11
3(3) - b = 11
9 - b = 11
-b = 11 - 9
-b = 2
b = -2
2a + 3b = 0
2(3) + 3b = 0
6 + 3b = 0
3b = 0 - 6
3b = -6
b = -6 / 3
b = -2
The answer would be (3,-2) if a =x and b = y