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LOGbase8 (X)/ X^2 I hope y'all can understand it, but it has to be derived
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so for me it would be \[\log_{8} X - \log_{8} X^2\]
I solved it just like this....
ohhhhh ok I get it, you reduced to 1/X and plan on subtracting both since they divide
yes you got it...
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but now how do you do the derivative of that?
derivative of log x is 1/x and for log 1 it would be zero because it is constant
oh alright, i got it thx!
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