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P(Z < z) = 0.2578 find z
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assuming a mean of 0 and a sd of 1 ?
yea
my first idea is to simply use a ztable to look up .2578 in its field
you got a ztable handy?
if not, you got a ti83 handy?
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yea theres no z score showing for 0.2578
add .5 to it
and pick the closest value :)
but that depends on the ztable itself; different authors use different constructs ....
are your value all larger than .5?
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yea
no, my largest vaule is .4990
then you should have the .2578 value in there, it wont be exact, but close
|dw:1336419556863:dw|
since the value is less than .5, we make the zscore itself negative
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|dw:1336419701306:dw|
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