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OpenStudy (anonymous):
How many moles of calcium hydroxide are needed to produce 73.7 milliliters of water, if the density of water is 0.987 g/mL? Show all steps of your calculation as well as the final answer. HCl + Ca(OH) 2 → H2O + CaCl2
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OpenStudy (anonymous):
2 HCl + Ca(OH)2 → 2 H2O + CaCl2 (73.7 mL) x (0.987 g/mL) / (18.0153 g H2O/mol) x (1/2) = 2.02 moles Ca(OH)2
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