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x^y=4096 what is the largest possible integer value for x-y
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you want to maximize x and minimize y here to get x-y to be largest. The values of x and y you would thus be looking for are x=4096 and y=1. x-y=4096-1=4095
you want to maximize the difference, D=x-y. substituting the constraint x^y=4096 ==> ylnx=ln4096 ==> y=(ln4096)/lnx, D = x - ln4096/lnx. differentiate D to find the x coordinate of the maximum value for D
dpalnc this is an sat question so it wouldnt have calculus but thx anyway
oopss sorry... :)
np :P
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