Question

How many different, positive four-degit integers, with no repeated digits, can be formed using the digits 0 through 9?

Answer 1

You're given 10 digits to work with, with no repetitions, and 4 choices. The formula for the number you're looking for is given by \[10P4={10! \over (10-4)!}\]

Answer 2

And order matters, which is why you have to use a permutation instead of a combination.

Answer 3

Thank you

Answer 4

You're welcome.