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find RANGE of function (2 x + 2)(x − 9) could u show me how to i forgot??
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the domain of the function is all valid inputs (x) the range of a function is all valid outputs (y) so another way to view this is what range of y values do you get from this?
find the second coordinate of the vertex, that will be the minimum value you have to multiply out first and make it look like \(ax^2+bx+c\) then use \(-\frac{b}{2a}\) fo the first coordinate
you should get \(2x^2-16x-18\) so vertex has first coordinate of \[-\frac{-16}{2\times 2}=4\] replace \(x\) by 4 to get the second coordinate of the vertex. since this is a parabola that opens up the range will be from there to \(\infty\)
thanks satellite!
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