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OpenStudy (anonymous):
I need to find an equation for the tangent to the curve at the given point. y=4-x^2 (-1,3)
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OpenStudy (anonymous):
y' = -2x y'(-1) = -2*(-1) = 2 is your slope... so the eqn of tangent line is : y - 3 = 2(x+1)
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