Which fact could you use to help prove that ΔABDΔACB using Side-Side-Side? A.∠ACB ≅ ∠DBA B.Line segment DB over line segment AD is equal to line segment BC over line segment AB C.Line segment AD is congruent to line segment CB. D.∠BAC + ∠BCA = 90˚
ΔABDΔACB --> Are you seeking to prove these triangles similar or something else? There is no symbol here. I think it must be a similarity symbol that is missing.
My bad yes I am
If Triangle ABD ~ Triangle ACB by SSS ~ Theorem, then the following extended proportion would have to be true: AB / AC = BD / CB = AD / AB ---------- Looking at this option: B.Line segment DB over line segment AD is equal to line segment BC over line segment AB This proportion DB / AD = BC / AB is equivalent to BD / BC = AD / AB which are two of the ratios of corresponding sides as shown above. So, B would be my choice. See what you think.
I have been thinking B was the answer but I wasn't positive so thats why I came on here to get a second opinon
I think you are correct about B.
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