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What are the solutions of the system? y=x^2+4x-5 y=2x-2
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y=x^2+4x-5 y=2x-2 so 2x-2 =x^2+4x-5 you will get X^2 + 2x - 3 = 0
(X + 3) ( x - 1)
y=x^2+4x-5 y= 2x-2 SUBTRATCTING, 0=x^2+2x-5
so x = - 3 or 1
@ashwinjohn3 You made a mistake
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where???
y=x^2+4x-5 y= 2x-2 SUBTRATCTING, 0=x^2+2x-3
@jit4won thanks...alot
x=-3,1
oops. @jit4won just said that :]
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Yeah ...Unfortunately I am too quick
canu guys do this question http://openstudy.com/study#/updates/4fa8c344e4b059b524f4b6c0?
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