Question

Solve √2x+3-√x+1=1

Answer 1

Put \[a=\sqrt{2x+3}\] and \[b=\sqrt{x+1}\],a,b>0
We have a system of equation :
first is \[a^2-2b^2=1\]
second is \[a-b=1\]

Answer 2

Is this the question?
\[\sqrt{2x}+3-\sqrt{x}+1=1\]

Answer 3

yeah

Answer 4

so I have a confusion for your exercise huh? =.=

Answer 5

Factorise as follows:
\[\sqrt{x}(\sqrt{2}-1)=-3\]
\[\sqrt{x}=-\frac{3}{\sqrt{2}-1}\]
\[x=\frac{9}{3-2\sqrt{2}}\]

Answer 6

Thanks i got it

Answer 7

You're welcome :)