Question

what's (e^ix)^2
where x is a variable

Answer 1

where\[i =\sqrt{-1}\]

Answer 2

it is e^i(2x)

Answer 3

If I integrate that from 0 to 2pi what will it be?

Answer 4

in respect to x

Answer 5

i is just a constant
the integration will be same as that for e^kx

Answer 6

e^(iPi)=cos x+i sin x

Answer 7

just treat i as a constant; you will be fine.