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Solve x2 + 6x + 7 = 0.
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use the formula
isn't it x^2+6x-7=0 ? (use formula if it is +7)
\[x=(-b \pm \sqrt{b ^{2}-4ac})/2a\]
Well if i know how to use the formula i would have answered the question
ax^2+bx+c=0 so a=1, b=6 and c=7
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is x^2+6x+7=0 ? if it is! that -3+radical of 2 -3-radical of 2
use vamgadu's formula
\[-3\pm \sqrt{2}\]
Is that correct thats what i got
yes
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