Question

given the function f(x)=(5-2x)(x+1)^2

what are the zeros and their multiplicities
y intercept
end behavior

Answer 1

zero points are when any of brackets equals 0 =>
(5-2x)=0
x+1=0

y-axis interception occurs when x=0:
(5-2*0)(0+1)^2

end behavior??? WTF? behavior when x approaches infinity?
it goes to -infinity, because of -2x

Answer 2

how do i know the multiplicity