Question

I cant remember the formula for this can anyone help?
Perimeter of a rectangle is 600 yards. What are the dimensions of the rectangle if the length is 80 yards more than the width?
thanks :)

Answer 1

Let the width be x.
So length = x + 80
2(l + b) = 600
2(x + 80 + x) = 600
Can you solve now?

Answer 2

p=2*(l+b)=600
l=b+80
solve these two equations

Answer 3

I can solve it but what does b stand for?

Answer 4

b is breadth or width.